When running the example from the README in a notebook I get the following error:
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
Cell In[2], line 7
4 import warnings
6 warnings.simplefilter('ignore')
----> 7 debugger = Debugger(view_type = "jupyter")
8 backend = FakeCasablanca()
9 circuit = random_circuit(num_qubits = 4, depth = 5 , seed = 44)
TypeError: Debugger() takes no argumentsIf I move view_type = "jupyter" to debugger.debug(... then the cell runs but I get a Javascript error instead. Here's from my browser console.
Error: Module @jupyter-widgets/controls, version ^1.5.0 is not registered, however, 2.0.0 is
loadClass http://localhost:8889/lab/extensions/@jupyter-widgets/jupyterlab-manager/static/134.fe2572ece3b7955c89bb.js?v=fe2572ece3b7955c89bb:1
loadModelClass http://localhost:8889/lab/extensions/@jupyter-widgets/jupyterlab-manager/static/336.0a90bd910629a565bb7e.js?v=0a90bd910629a565bb7e:1
_make_model http://localhost:8889/lab/extensions/@jupyter-widgets/jupyterlab-manager/static/336.0a90bd910629a565bb7e.js?v=0a90bd910629a565bb7e:1
new_model http://localhost:8889/lab/extensions/@jupyter-widgets/jupyterlab-manager/static/336.0a90bd910629a565bb7e.js?v=0a90bd910629a565bb7e:1
handle_comm_open http://localhost:8889/lab/extensions/@jupyter-widgets/jupyterlab-manager/static/336.0a90bd910629a565bb7e.js?v=0a90bd910629a565bb7e:1
_handleCommOpen http://localhost:8889/lab/extensions/@jupyter-widgets/jupyterlab-manager/static/134.fe2572ece3b7955c89bb.js?v=fe2572ece3b7955c89bb:1
_handleCommOpen http://localhost:8889/static/notebook/3676.bundle.js:1
Relevant version info
qiskit==0.43.0
qiskit-aer==0.12.0
qiskit-ibmq-provider==0.20.2
qiskit-ignis==0.7.0
qiskit-terra==0.24.0
qiskit-trebugger==1.1.2
jupyter-events==0.9.0
jupyter-lsp==2.2.4
jupyter_client==8.6.0
jupyter_core==5.7.1
jupyter_server==2.13.0
jupyter_server_terminals==0.5.2
jupyterlab==4.1.4
jupyterlab_pygments==0.3.0
jupyterlab_server==2.25.3
jupyterlab_widgets==3.0.10
When running the example from the README in a notebook I get the following error:
--------------------------------------------------------------------------- TypeError Traceback (most recent call last) Cell In[2], line 7 4 import warnings 6 warnings.simplefilter('ignore') ----> 7 debugger = Debugger(view_type = "jupyter") 8 backend = FakeCasablanca() 9 circuit = random_circuit(num_qubits = 4, depth = 5 , seed = 44) TypeError: Debugger() takes no argumentsIf I move
view_type = "jupyter"todebugger.debug(...then the cell runs but I get a Javascript error instead. Here's from my browser console.Relevant version info