Fix Any inference when unpacking iterators that don't directly inherit from typing.Iterator#14821
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JukkaL merged 2 commits intopython:masterfrom Mar 3, 2023
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…on't directly inherit from `typing.Iterator`
Any inference when unpacking iterators that return self and don't directly inherit from typing.IteratorAny inference when unpacking iterators that don't directly inherit from typing.Iterator
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sobolevn
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Mar 3, 2023
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Nice to see this ad-hoc code removed!
| def __iter__(self): pass | ||
| def __next__(self): pass | ||
| a, b = Nums() | ||
| reveal_type(a) # N: Revealed type is "builtins.int" |
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The other option here is to infer Any, because of def __iter__(self): pass
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Yup, but as discussed in the issue, two long-standing tests fail if I make that change, so I'd rather not make that behaviour change in this PR 👍
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According to mypy_primer, this change has no effect on the checked open source code. 🤖🎉 |
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Fixes #14819.
Mypy currently silently infers an
Anytype when unpacking an iterator that doesn't explicitly inherit fromtyping.Iterator(i.e., an iterator that's a structural subtype oftyping.Iterator, but not a nominal subtype):However, we have enough information here to infer that the type of
ashould really beint. This PR fixes that bug.There's discussion on the issue thread about an alternative solution that would involve changing some mypy behaviour that's been established for around 10 years. For now, I haven't gone for that solution.